Question

How many atoms are in 56.87 moles of AgNO3?

Answer 1

We now that 6.022x10^23 atoms are in one mole, therefore:

`56.87mol\text{ }AgNO_3*\frac{6.022*10^(23)mol}{1mol\text{ }AgNO_3}=3.425*10^{25\text{ }}molAgNO_3`

Answer: 3.425x10^35 mol AgNO3