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How many atoms are in 56.87 moles of AgNO3?

1 Answer

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We now that 6.022x10^23 atoms are in one mole, therefore:


56.87mol\text{ }AgNO_3*\frac{6.022*10^(23)mol}{1mol\text{ }AgNO_3}=3.425*10^{25\text{ }}molAgNO_3

Answer: 3.425x10^35 mol AgNO3

User Michael Carman
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