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EJERCICIO DE ESTADISTICAThe time (in minutes) between telephone calls at an insurance claims office has the exponential probability distributionf(x) = 0.50 e-0.50x for x ≥ 0.a. what is the mean time between phone calls?b. what is probability of 30 seconds or less between phone calls?c. what is probability of 1 minute or less between phone calls?d. what is probability of 5 or more minutes without a phone call?

User Mindoftea
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1 Answer

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Given

Exponential probability distribution


f\mleft(x\mright)=0.50e^(-0.50x),x≥0.

Find

a) what is the mean time between phone calls?

b) what is probability of 30 seconds or less between phone calls?

c) what is probability of 1 minute or less between phone calls?

d) what is probability of 5 or more minutes without a phone call?

Step-by-step explanation

given


f\mleft(x\mright)=0.50e^(-0.50x),x≥0.

formula for the probability exponential distribution is given by


\begin{gathered} P(x\leq a)=1-e^{-(a)/(\mu)} \\ P(aa) the mean is the reciprocal of the constant , so[tex]\mu=(1)/(0.50)=2

b) probability of 30 seconds or less between phone calls is


P(x\leq0.50)=1-e^{-(0.50)/(2)}\approx0.2212

c) probability of 1 minute or less between phone calls


P(x\leq1)=1-e^{-(1)/(2)}\approx0.3935

d)

probability of 5 or more minutes without a phone call


P(x\ge5)=e^{-(5)/(2)}\approx0.0821

Final Answer

Therefore ,

a) 2 minutes

b) 0.2212

c) 0.3935

d) 0.0821

User Singuliere
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