Given
Exponential probability distribution
![f\mleft(x\mright)=0.50e^(-0.50x),x≥0.](https://img.qammunity.org/2023/formulas/mathematics/college/3dmurq1r15uwgd8ln7phbip3wv9ilha1vw.png)
Find
a) what is the mean time between phone calls?
b) what is probability of 30 seconds or less between phone calls?
c) what is probability of 1 minute or less between phone calls?
d) what is probability of 5 or more minutes without a phone call?
Step-by-step explanation
given
![f\mleft(x\mright)=0.50e^(-0.50x),x≥0.](https://img.qammunity.org/2023/formulas/mathematics/college/3dmurq1r15uwgd8ln7phbip3wv9ilha1vw.png)
formula for the probability exponential distribution is given by
![\begin{gathered} P(x\leq a)=1-e^{-(a)/(\mu)} \\ P(aa) the mean is the reciprocal of the constant , so[tex]\mu=(1)/(0.50)=2]()
b) probability of 30 seconds or less between phone calls is
![P(x\leq0.50)=1-e^{-(0.50)/(2)}\approx0.2212](https://img.qammunity.org/2023/formulas/mathematics/college/eprdagt14w1z5kb4hiw7jhoukxygs6jenl.png)
c) probability of 1 minute or less between phone calls
![P(x\leq1)=1-e^{-(1)/(2)}\approx0.3935](https://img.qammunity.org/2023/formulas/mathematics/college/63fp339eshmowg98yhpozibb9p4w8pr8v1.png)
d)
probability of 5 or more minutes without a phone call
![P(x\ge5)=e^{-(5)/(2)}\approx0.0821](https://img.qammunity.org/2023/formulas/mathematics/college/csu6h3vzrpt3imzi6spxmvbcvkq2czywg6.png)
Final Answer
Therefore ,
a) 2 minutes
b) 0.2212
c) 0.3935
d) 0.0821