53.6k views
0 votes
23. Express the following in the form a+bi. 11^7 − 2^5 + 5 − 11a. 11+8i b. -11+8i c. -11-8i d. -8+11i e. 8+11i

User Cui Mingda
by
8.9k points

1 Answer

4 votes

We have the following complex number:


11i^7-2i^5+5i-11

Let's begin by noting how the powers of i work. To begin with, let's remember that


i=\sqrt[]{-1}\text{.}

Knowing that:


i^1=i,
i^2=(\sqrt[]{-1})^2=-1,
i^3=i^2\cdot i=-1\cdot i=-i,
i^4=i^2\cdot i^2=(-1)(-1)=1.

Now, notice that


i^5=i^4\cdot i=1\cdot i=i,

so the powers of i actually repeat after four integers. In other words:


i^1=i^5=i^9=i^(13)=\ldots
i^2=i^6=i^(10)=i^(14)=\ldots
i^3=i^7=i^(11)=i^(15)=\ldots
i^4=i^8=i^(12)=i^(16)=\ldots

This also works the same way for negative powers. Now that we know this, let's focus on the powers of i on the number we were given:


i^7=i^3=-i,

so


11i^7=-11i\text{.}
i^5=i,

so


-2i^5=-2i\text{.}

Putting all of them together:


11i^7-2i^5+5i-11=-11i-2i+5i-11=-8i-11=-11-8i\text{.}

So, the correct answer is option c.

User Jsight
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories