Given:

Step-by-step explanation:
a) To find: Range
The range formula is,

Therefore, the range of the data is 1.8.
b) To find: The standard deviation.
The formula is,

Here,

On substitution we get,
![\begin{gathered} \sigma=\sqrt{((9.5-9.55)^2+(9.1-9.55)^2+(9.7-9.55)^2+(9.5-9.55)^2+(9.2-9.55)^2+(10.5-9.55)^2+(10.3-9.55)^2+(9.1-9.55)^2+(9.9-9.55)^2+(9.5-9.55)^2+(8.7-9.55)^2)/(11-1)} \\ =\sqrt{(2.86727)/(10)} \\ =√(0.286727) \\ =0.5354 \\ \sigma\approx0.54 \end{gathered}]()
Therefore, the standard deviation for the given data is,

c) To find: Variance
Since the standard deviation is 0.54.
So, the variance becomes,

Final answer:
• The range of the data is 1.8.
,
• The standard deviation for the given data is 0.54.
,
• The variance for the given data is 0.29.