Question

Find the discriminant of x^2+14x+17=4

Answer 1

`x^2+14x+17=4`

first we set the equation to zero

`\begin{gathered} x^2+14x+17-4=0 \\ x^2+14x+13=0 \end{gathered}`

now identify the coefficients

a is 1, b is 14 and c is 13

Then use the formula of the discriminant

`b^2-4ac`

and replace

`\begin{gathered} (14)^2-4(1)(13) \\ 196-52 \\ =144 \end{gathered}`

the discriminant value is 144

Factor formula

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

the discriminant is the one found within the root