Given:
Vincent’s plane cruised at an altitude of
![\text{3}.2*10^4](https://img.qammunity.org/2023/formulas/mathematics/college/jeh1tw147c9tb0qxmbdib6lfgo8kitr34g.png)
He had heard that a man named Felix Baumgartner skydived from an altitude of
![1.28*10^5](https://img.qammunity.org/2023/formulas/mathematics/college/dyxyuyoizgighk51cz8c2gnms59lswc62m.png)
Part A
Write the cruising altitude of Vincent’s plane in standard notation.
So, the answer will be =
![3.2*10^4=3.2*10000=32000](https://img.qammunity.org/2023/formulas/mathematics/college/ta9sfxq15fxifhaaf8guz35iu6uwtg7q5b.png)
Part B
Write Felix’s skydiving altitude in standard notation.
So, the answer will be =
![\text{1}.28*10^5=1.28*100000=128000](https://img.qammunity.org/2023/formulas/mathematics/college/zcynmpyl5dgs8xd6hy9vgfnlf3dyl2hu24.png)
Part C
What is the difference between the altitude of Vincent’s plane and Felix’s skydiving altitude?
So, the answer will be =
![128000-32000=96000](https://img.qammunity.org/2023/formulas/mathematics/college/nvj8ecjzglcdhulxu4r4myjp6wfbo23apx.png)
Part D
Convert the difference of the altitudes from standard notation to scientific notation.
So, the answer will be =
![96000=9.6*10^4](https://img.qammunity.org/2023/formulas/mathematics/college/2ret5i3759cfdn9wp985mao6yeigu16af3.png)
Now, We will solve the problem using scientific notation.
Part A
Transform Vincent’s plane’s altitude in scientific notation so that it has the same power of 10 as Felix’s altitude.
so, the answer will be =
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