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What is the approximate sector area of a sector defined by minor arc overline CB m angle CAD=84^ BD=6 cm

What is the approximate sector area of a sector defined by minor arc overline CB m-example-1
What is the approximate sector area of a sector defined by minor arc overline CB m-example-1
What is the approximate sector area of a sector defined by minor arc overline CB m-example-2
User FZE
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1 Answer

3 votes

The formula for the area of a sector of a circle is:


A=(\theta)/(360)*\pi r^2

We want to find the area of the blue sector.

First, let's find the angle of the sector. This angle and angle 84 are in a straight line. Thus, we can say:


\theta+84=180

Where θ is the angle of the sector.

Let's solve for θ:


\begin{gathered} \theta+84=180 \\ \theta=180-84 \\ \theta=96 \end{gathered}

We also recognize that BD is the diameter and BA is the radius.

We know

Radius is HALF of Diameter.

Given,

Diameter = 6

Radius = 6/2 = 3

Now, let's calculate the area of the sector:


\begin{gathered} A=(\theta)/(360)*\pi r^2 \\ A=(96)/(360)*\pi(3)^2 \\ A=(4)/(15)*9\pi \\ A=(36\pi)/(15) \end{gathered}

Rounded to 2 decimal places,

Answer

Area = 7.54 sq. cm.

User Phaylon
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