JK has coordinates J(9,-3) and K(-1,5). If LM os perpendicular to JK what is the slope of LM? Write answer as either an a integer or a simplified fraction. NO DECIMAL

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asked May 22, 2023 7.9k views

1 Answer

Diony · Answer 1 · 2023-05-27T23:33:41+0000

Given data:

The first coordinate is J(9,-3).

The second coordinate is K(-1,5).

The slope of the line passing through the given points is,

$\begin{gathered} m=(5-(-3))/(-1-9) \\ =(8)/(-10) \\ =-0.8 \end{gathered}$

The slope of the line LM perpendicular to it is,

$\begin{gathered} m^(\prime)* m=-1 \\ m^(\prime)*(-0.8)=-1 \\ m=(1)/(0.8) \\ =(5)/(4) \end{gathered}$

Thus, the slope of the LM line is 5/4.