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What's the acceleration of gravity on a planet that has a gravitational pull that is 1/2 that ofEarth? (Round to tenth's place.)

User Mycah
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1 Answer

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The gravitational pull of the earth is:


g=9.8(m)/(s^2)

Half this gravitational pull is:


(g)/(2)=(9.8)/(2)(m)/(s^2)

Solving the operations:


(g)/(2)=4.9(m)/(s^2)

Therefore, the gravitational pull of the planet is 4.9 meters per second squared.

User PEdroArthur
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