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Assume that adults have IQ scores that are normally distributed with a mean of 100.4 and a standard deviation 19.7. Find the first quartile Q1, which is the IQ scoreseparating the bottom 25% from the top 75%. (Hint: Draw a graph.)The first quartile is?

User Aliou
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The first quartile is the number in between the lowest number of a data set and the median. To find it, I would use a Z table as shown below

The z score that corresponds to 0.25 is -0.67 on the table above.

Using the equation of z-score below


\begin{gathered} z=(x-\mu)/(\sigma) \\ \text{Where}\mu=\operatorname{mean},\sigma=s\tan dard\text{ deviation} \end{gathered}

Where x is the value we're looking for and σ and μ are the standard deviations and the mean given in the problem.

Given that the mean is 100.4 and the standard deviation is 19.7, make x the subject of the z-score formula and substitute for the mean and standard deviation as shown below


\begin{gathered} z=(x-\mu)/(\sigma) \\ x-\mu=z*\sigma \\ x=z*\sigma+\mu \\ z=-0.67,\mu=100.4,\sigma=19.7 \end{gathered}
\begin{gathered} x=-0.67*19.7+100.4 \\ x=-13.199+100.4 \\ x=87.201 \end{gathered}

Hence, the first quartile is 87.201

Assume that adults have IQ scores that are normally distributed with a mean of 100.4 and-example-1
User Shamseer K
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