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If you have 22.42 grams of HC1, how many grams of MnCl2

If you have 22.42 grams of HC1, how many grams of MnCl2-example-1

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Answer:


232.14\text{ grams}

Step-by-step explanation:

Here, we want to get the mass of manganese chloride

We start by getting the number of moles of HCl

Mathematically:


number\text{ of moles = }\frac{mass}{molar\text{ mass}}\text{ = }(22.42)/(36.46)\text{ = 0.615 mol}

From the information given, 1 mole of Hcl produces 3 moles of MnCl2

Thus, the number of moles of MnCl2 produced will be:


0.615\text{ }*\text{ 3 = 1.84 mol}

Finally, to get the mass, we multiply the above number of moles by the molar mass of MnCl2

Mathematically, we have that as:


1.84\text{ }*\text{ 125.84 = 232.14 grams}

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