Question

In Triangle LMN, l = 3.9 cm, m = 2.7 cm and angle N=133º. Find the area ofTriangle LMN, to the nearest 10th of a square centimeter.

Answer 1

Given the information, we have the following triangle:

then, we can use the formula for the area of the triangle given two sides and the angle between them:

`A=(a\cdot b\cdot\sin (c))/(2)`

where a, b are the two sides and c is the angle.

In this case, we have the following:

`\begin{gathered} a=l=3.9 \\ b=m=2.7 \\ c=\measuredangle N=133 \end{gathered}`

then, using the formula we have the following:

`A=((3.9)(2.7)\sin(133))/(2)=((10.53)(\sin (133)))/(2)=(7.7)/(2)=3.9`

therefore, the area is 3.9cm^2