Question

Given a triangle ABC at points A = ( 3, 5 ) B = ( 1, 6 ) C = ( 7, 1 ), and a first transformation of right 1 and up 2, and a second transformation of left 6 and down 4, what would be the location of the final point B'' ?

Answer 1

B'' (-4, 4)

1) Given that this triangle ABC has the following points located at A =(3,5), B=(1,6), and C=(7,1).

2) Let's focus on point B, and apply the following transformations:

1st Translation

(x, y) --> (x+1, y+2)

B (1,6)---> B' (2,8)

2nd Translation

(x, y) --> (x-6, y-4)

B'(2,8)--->B'' (-4, 4)

3) Thus, the final location of point B'' is (-4, 4)