Question

Question number 6 Find the length of each arc. Write answer in terms of π.

Answer 1

`L_{major\text{ arc}}=(\theta)/(360)*2\pi r`
`\text{Where r=16ft and }\theta=(3\pi)/(2)`
`\begin{gathered} L_{major\text{ arc}}=(3\pi)/(2*360)*2\pi*16 \\ L_{major\text{ arc}}=(4)/(15)\pi^2 \end{gathered}`
`\begin{gathered} \text{The arc subtended by the minor arc is} \\ 2\pi-(3\pi)/(2)=(\pi)/(2) \end{gathered}`
`\begin{gathered} L_{\min or\text{ arc}}=(\pi)/(2*360)*2\pi*16 \\ L_{\min or\text{ arc}}=(2)/(45)\pi^2 \end{gathered}`