To answer this question, we need to take into account that we have here operations with mixed fractions. Then, we can pose the operations as follows:
1. We have a total of 68 and 3/4 acres.
2. How many acres of wooded land will remain if we subtract 4/5 acres from the total?
Then, we can proceed as follows:
![68(3)/(4)=68+(3)/(4)=(68\cdot4+1\cdot3)/(4)=(272+3)/(4)=(275)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/rnkh20srhu7kci1st093rpki9q7xvxq8up.png)
Thus, we have that 4/5 from the total is:
![(275)/(4)\cdot(4)/(5)=(1100)/(20)=(110)/(2)=55](https://img.qammunity.org/2023/formulas/mathematics/college/a85f7ph8xq3x6hqyaxk9bdyvk4cvz9iqyw.png)
We have that 55 acres are cleared for development. We have at the beginning 275/4 acres (68 plus 3/4 acres). Now, we need to subtract 55 acres from the latter. Then, we have:
![(275)/(4)-55=(275\cdot1-55\cdot4)/(4)=(275-220)/(4)=(55)/(4)=(52)/(4)+(3)/(4)=13+(3)/(4)=13(3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/8l4dzd1dtllxb1msxehreyji94ce9qke3j.png)
Therefore, there will remain 13 and 3/4 of acres of wooded land (first option).
(As we can see this last value is 1/5 of the total acres of the wooded piece of land.)