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Solve the equation for all values of x by completing the square. x²-18x+68=0
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Solve the equation for all values of x by completing the square. x²-18x+68=0

User Simon Lomax
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1 Answer

3 votes

Given


x^2-18x+68=0

Procedure


\begin{gathered} x^2-18x+81-81+68=0 \\ (x-9)^2=13 \\ x-9=\pm\sqrt[]{13} \\ \\ x=9+\sqrt[]{13} \\ x=9-\sqrt[]{13} \end{gathered}

User Pawel Veselov
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