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(11/2)x2y – (9/4)xy2 + (1/4)xy - (1/14)y2x + (1/15) yx2 + (1/2)xy

1 Answer

4 votes

(167)/(30)yx^2-(65)/(28)y^2x+(3)/(4)xy

Step-by-step explanation


(11)/(2)x^2y-(9)/(4)xy^2+(1)/(4)xy-(1)/(14)y^2x+(1)/(15)yx^2+(1)/(2)xy

Step 1

group similar terms


\begin{gathered} (11)/(2)x^2y-(9)/(4)xy^2+(1)/(4)xy-(1)/(14)y^2x+(1)/(15)yx^2+(1)/(2)xy \\ ((11)/(2)x^2y+(1)/(15)yx^2)+(-(9)/(4)xy^2-(1)/(14)y^2x)+((1)/(2)xy+(1)/(4)xy) \end{gathered}

Step 2

add similar terms


\begin{gathered} ((11)/(2)x^2y+(1)/(15)yx^2)+(-(9)/(4)xy^2-(1)/(14)y^2x)+((1)/(2)xy+(1)/(4)xy) \\ ((11)/(2)+(1)/(15))(yx^2)+(-(9)/(4)-(1)/(14))(y^2x)+((1)/(2)+(1)/(4))(xy) \\ (167)/(30)yx^2-(65)/(28)y^2x+(3)/(4)xy \end{gathered}

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