Question

(11/2)x2y – (9/4)xy2 + (1/4)xy - (1/14)y2x + (1/15) yx2 + (1/2)xy

Answer 1

`(167)/(30)yx^2-(65)/(28)y^2x+(3)/(4)xy`

Step-by-step explanation

`(11)/(2)x^2y-(9)/(4)xy^2+(1)/(4)xy-(1)/(14)y^2x+(1)/(15)yx^2+(1)/(2)xy`

Step 1

group similar terms

`\begin{gathered} (11)/(2)x^2y-(9)/(4)xy^2+(1)/(4)xy-(1)/(14)y^2x+(1)/(15)yx^2+(1)/(2)xy \\ ((11)/(2)x^2y+(1)/(15)yx^2)+(-(9)/(4)xy^2-(1)/(14)y^2x)+((1)/(2)xy+(1)/(4)xy) \end{gathered}`

Step 2

add similar terms

`\begin{gathered} ((11)/(2)x^2y+(1)/(15)yx^2)+(-(9)/(4)xy^2-(1)/(14)y^2x)+((1)/(2)xy+(1)/(4)xy) \\ ((11)/(2)+(1)/(15))(yx^2)+(-(9)/(4)-(1)/(14))(y^2x)+((1)/(2)+(1)/(4))(xy) \\ (167)/(30)yx^2-(65)/(28)y^2x+(3)/(4)xy \end{gathered}`