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In a circle, the perpendicular bisector of a chord contains the center of the circle.Given : O X with L the 1 bisector of WY.Prove: L contains the center of O X.

In a circle, the perpendicular bisector of a chord contains the center of the circle-example-1
User Boneist
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All radii of the circle are congruent.Therefore, the radii XW and XY are congruent


\begin{gathered} XW\cong XY \\ \end{gathered}

User TheGeekNess
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