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Who discover the head of a match contains 3.75 g of sulfur how many atoms of sulfur does the match contain?

User Zorayr
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1 Answer

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Step-by-step explanation:

The head of a match contains 3.75 g of sulfur. We have to find the number of sulfur atoms that are present there. To go from grams to atoms, we will have to convert from grams to moles and then from moles to atoms.

To convert the mass into moles we can use the molar mass of S.

mass of S = 3.75 g

molar mass of S = 32.07 g/mol

moles of S atoms = 3.75 g * 1 mol/(32.07 g)

moles of S atoms = 0.117 moles

Then according to Avogadro's number there are 6.022 *10^23 atoms in 1 mol of atoms. We can use that relationship to find the answer to our problem.

1 mol of S atoms = 6.022 * 10^23 atoms

atoms of S = 0.117 moles * 6.022 * 10^23 atoms/mol

atoms of S = 7.05 *10^22 atoms

Answer: the match contains 7.05 * 10^22 atoms of S.

User Breanne
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