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A fair die is tossed. The following table represents the probability distribution of the experiment.

A fair die is tossed. The following table represents the probability distribution-example-1

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To get the standard deviation of the probability distribution, we will use the formula below


\sigma=\sqrt[]{\sum ^{}_{}(x-\bar{x})^2* P(x)}

where


\begin{gathered} \bar{x}=mean \\ x=\text{value } \\ P(x)=\text{probability of the value occurring} \end{gathered}

Step 1: To begin with, we will get the mean first


\bar{x}=1*0.12+2*0.25+3*0.13+4*0.1+5*0.1+6*0.3=3.71


\bar{x}=3.71

Next, we will find


\begin{gathered} \sum ^{}_{}(x-\bar{x})^2* p(x)=0.12(1-3.71)^2+0.25(2-3.71)^2+0.13(3-3.71)^2+0.1(4-3.71)^2+0.1(5-3.71)^2+0.3(6-3.71)^2 \\ =3.4259 \end{gathered}

The final step will be to find the square root of the value obtained above


\sqrt[]{\sum ^{}_{}(x-\bar{x})^2* p(x)}=\sqrt[]{3.4259}=1.851

From the options provided, the closest answer is 1.84

Thus, the answer is 1.84

User Manveti
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