Question

In a valid probability distribution, each probability must be between 0 and 1,inclusive, and the probabilities must add up to 1. If a probability distribution5has probabilities1,112, and x, what is the value of X?

Answer 1

Given:

The probability distribution is given by,

`(5)/(12),(1)/(6),(1)/(3),x`

To find:

The value of x.

Step-by-step explanation:

We know that,

The probabilities must add up to 1.

So, we write

`(5)/(12)+(1)/(6)+(1)/(3)+x=1`

Solving for x we get

`\begin{gathered} x=1-(5)/(12)-(1)/(6)-(1)/(3) \\ x=(12-5-2-4)/(12) \\ x=(1)/(12) \end{gathered}`

Therefore, the value of x is,

`(1)/(12)`

Final answer: Option D

The value of x is,

`(1)/(12)`