I got to find c and round to the nearest hundredth

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asked May 7, 2023 186k views

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Tsergium · Answer 1 · 2023-05-11T09:04:13+0000

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Draw the given right-angled triangle

STEP 2: Determine the trigonometric ratio to use

$\begin{gathered} Given: \\ opposite=9,hypotenuse=c,\theta=45^^(\circ) \\ \\ Since\text{ we have the opposite and hypotenuse, we use:} \\ sin\theta=(opp)/(hyp) \end{gathered}$

STEP 3: Substitute the given values and solve for c

$\begin{gathered} \sin45=(9)/(c) \\ By\text{ cross multiplication,} \\ c*\sin45=9 \\ Divide\text{ both sides by sin 45} \\ (c*\sin(45))/(sin45)=(9)/(sin45) \\ c=12.72792206 \\ c\approx12.73 \end{gathered}$

Hence, the value of c is approximately 12.73

I got to find c and round to the nearest hundredth-example-1

I got to find c and round to the nearest hundredth

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