Question

A 2kg ball rolls down a frictionless ramp of height 5m, at the end of the ramp what will its velocity be? Model solutions for each example must be presented using the GRASP process.

Answer 1

Given:

The mass of the ball, m=2 kg

The height of the ramp, h=5 m

To find:

The velocity of the ball at the end of the ramp.

Step-by-step explanation:

From the law of conservation of energy, the total energy of the ball must rmain the sam. That is the potential energy of the balla at the top of the sramp must be equal to the kinetic energy of the ball at the bottom of the ramp.

Thus,

`\begin{gathered} mgh=(1)/(2)mv^2 \\ \implies v=√(2gh) \end{gathered}`

Where g is the acceleration due to gravity and v is the velocity of the ball at the end of the ramp.

On substitutin the known values,

`\begin{gathered} v=√(2*9.8*5) \\ =10\text{ m/s} \end{gathered}`

Thus the velocity of the ball at the end of the ramp is 10 m/s