Answer:
Step-by-step explanation:
Let us sketch the angle ø.
As can be seen from the triangle above,

Furthermore,

we just need to find the value of x.
To find the value of x, we use pythagoras's theorem.


subtracting 1 from both sides gives


taking the sqaure root of both sides gives

with the value of x in hand, we now have


which is our answer!