Question

So im trying to dind the data tabls numbers and the equation

Answer 1

the equation fro the line can be written in the slope-intercept form,

for that we would need to find the slope and the y intercept on the line,

the slope can be found by using two of the points from the line.

the points we are selecting are (20,32) and (30,45) which are points that are approximate to the line drawn.

use the points given and the definition of the slope to find it:

`m=(y_2-y_1)/(x_2-x_1)`

It should look something like this

`\begin{gathered} m=(45-32)/(30-20) \\ m=(13)/(10) \end{gathered}`

according to the graph the intercept is the point it crosses the y-intercept which in this case is 10.

the equation of the line will be

`y=(13)/(10)x+10`

Using the equation of the line construct the data table by giving the values for x

0-10-20-30-40-50

it should look like this

in order to find the y side we use the equation, i will do an example with x as 10

`\begin{gathered} y=(13)/(10)\cdot(10)+10 \\ y=13+10 \\ y=23 \end{gathered}`

apply the same to find the corresponding value to each x.

finish by making the exact graph for the equation and data table we just found