176k views
4 votes
In a physics lab a student discovers that the magnitude of the magnetic field in a specific location near a long wire is 22.537 microTesla. If the wire carries a current of 73.298 A, what is the distance from the wire to that location ?

User Audrina
by
8.3k points

1 Answer

5 votes

Given:

The magnitude of the magnetic field is,


\begin{gathered} B=22.537\text{ }\mu T \\ =22.537*10^(-6)\text{ T} \end{gathered}

The current in the wire is,


i=73.298\text{ A}

To find:

The distance from the wire to that location

Step-by-step explanation:

The magnetic field due to a current-carrying wire at a distance 'r' is,


B=(\mu_0i)/(2\pi r)

Here,


\mu_0=4\pi*10^(-7)\text{ H/m}

Substituting the values we get,


\begin{gathered} 22.537*10^(-6)=(4\pi*10^(-7)*73.298)/(2\pi r) \\ r=(4\pi*10^(-7)*73.298)/(2\pi*22.537*10^(-6)) \\ r=0.65\text{ m} \end{gathered}

Hence, the required distance from the wire is 0.65 m.

User Omeralper
by
7.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.