Question

In a physics lab a student discovers that the magnitude of the magnetic field in a specific location near a long wire is 22.537 microTesla. If the wire carries a current of 73.298 A, what is the distance from the wire to that location ?

Answer 1

Given:

The magnitude of the magnetic field is,

`\begin{gathered} B=22.537\text{ }\mu T \\ =22.537*10^(-6)\text{ T} \end{gathered}`

The current in the wire is,

`i=73.298\text{ A}`

To find:

The distance from the wire to that location

Step-by-step explanation:

The magnetic field due to a current-carrying wire at a distance 'r' is,

`B=(\mu_0i)/(2\pi r)`

Here,

`\mu_0=4\pi*10^(-7)\text{ H/m}`

Substituting the values we get,

`\begin{gathered} 22.537*10^(-6)=(4\pi*10^(-7)*73.298)/(2\pi r) \\ r=(4\pi*10^(-7)*73.298)/(2\pi*22.537*10^(-6)) \\ r=0.65\text{ m} \end{gathered}`

Hence, the required distance from the wire is 0.65 m.