We know that f(2) = 7
a f(2) = | 2*2 -5| +6 = |4-5| +6 = |-1| +6 = 1+6 = 7 this works
b f(2) x^2+1 = 2^2 +1 = 4+1 = 5 This is not 7
c f(2) = [2*2+3] = [4+3] = [7] = 7 this is 7
d f(2) =2[2]+3 = 4+3 = 7
All but b are true
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