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Write the equation of the line that passes through (4,-2) and (-4,-4)A) y = 1/4x - 3B) y = 3/4x - 5C) y = - 2D y = - 3/4x + 1

1 Answer

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Let:


\begin{gathered} (x1,y1)=(4,-2) \\ (x2,y2)=(-4,-4) \end{gathered}

The slope of the line is given by:


m=(y2-y1)/(x2-x1)=(-4-(-2))/(-4-4)=(-2)/(-8)=(1)/(4)

Using the point-slope equation:


\begin{gathered} y-y1=m(x-x1) \\ y+2=(1)/(4)(x-4) \\ y+2=(1)/(4)x-1 \\ y=(1)/(4)x-1-2 \\ y=(1)/(4)x-3 \end{gathered}

Answer:

A) y = 1/4x - 3

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