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Determine if the lines are perpendicular y=2/3x+13y+2x=4

User Gzh
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3 votes

Answer:

No, the lines are not perpendicular

Step-by-step explanation:

Two lines are perpendicular if the multiplication of their slopes is equal to -1.

Therefore, we first need to identify the slopes of each equation:

For y = (2/3)x+1, the slope is 2/3 because it is the number beside the x.

On the other hand, to know the slope of the equation 3y + 2x = 4, we need to solve for y, so:


\begin{gathered} 3y+2x=4 \\ 3y+2x-2x=4-2x \\ 3y=-2x+4 \\ (3y)/(3)=(-2x)/(3)+(4)/(3) \\ y=-(2)/(3)x+(4)/(3) \end{gathered}

Therefore, the slope of the second equation is -2/3

Then, the multiplication of 2/3 by -2/3 is equal to:


(2)/(3)*-(2)/(3)=(2*(-2))/(3*3)=-(4)/(9)

Since -4/9 and -1 are distinct, the lines are not perpendicular.

User Anders Elton
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