Given:
The takeoff velocity of the plane, v=300 km/hr
The acceleration of the plane, a=1 m/s²
To find:
The average velocity of the plane.
Step-by-step explanation:
The initial velocity of the plane is u=0 m/s
The take-off velocity of the plane in m/s is

The average velocity of an object having a constant acceleration is given by the sum of the initial and final velocity divided by two.
Thus the average velocity of the plane until it takes off is given by,

From the equation of motion,

Where d is the takeoff distance.
On substituting the known values,

Final answer:
Thus the average velocity of the plane is 41.7 m/s
Thus the takeoff distance is 3471.9 m