Given:
Equation of a circle is
![(x-4)^2+(y+3)^2=29](https://img.qammunity.org/2023/formulas/mathematics/college/ckaqawdk6d2qvvynmo9y7qfhwsgy0po9r5.png)
Required:
What is the center and the radius of the circle?
Step-by-step explanation:
In a circle, if the coordinate of the center are (h, k), r is the radius, and (x, y) is any point on the circle., then the center of circle formula is given by
![(x-h)^2+(y-k)^2=r^2](https://img.qammunity.org/2023/formulas/mathematics/college/5s77z5lwu6jnvb5vkwanu2jvhq5sh1qkc3.png)
Now, we have equation
![(x-4)^2+(y+3)^2=29](https://img.qammunity.org/2023/formulas/mathematics/college/ckaqawdk6d2qvvynmo9y7qfhwsgy0po9r5.png)
![\text{ In which center }(h,k)=(4,-3)\text{ and radius }√(29).](https://img.qammunity.org/2023/formulas/mathematics/college/b846gjduwolomi5s49q7p952gxge82ua2s.png)
Answer:
Hence, above is the center and radius of circle.