Question

4) Find the area of each composite figure. 2.5 in 2.5 in 6 in in? 4.2 in А = square A trapezoid ina А figure 1/1

Answer 1

The figure is a combination of a square and a trapezoid;

Thus, we first look for the area of a square using the formula below;

`\begin{gathered} A_(square)=length* length \\ \text{Where the length of the square is 2.5in} \\ A_(square)=2.5*2.5 \\ A_(square)=6.25in^2 \end{gathered}`

Answer: The area of the square is 6.25 square inches.

Also, we find the area of the trapezoid using the formula below;

`\begin{gathered} A_(trapezoid)=(1)/(2)(a+b)h \\ \text{Where a and b are the upper length and the bottom length respectively } \\ a\text{ is the length of the square = 2.5in} \\ b=\text{ 4.2in} \\ \text{h is the height = 6in} \\ A_(trapezoid)=(1)/(2)(2.5+4.2)6 \\ A_(trapezoid)=3(6.7) \\ A_(trapezoid)=20.1in^2 \end{gathered}`

Answer: The area of the trapezoid is 20.1 square inches.

`\begin{gathered} A_(figure)=A_(square)+A_(trapezoid) \\ A_(figure)=6.25in^2+20.1in^2 \\ A_(figure)=26.35in^2 \end{gathered}`

Answer: The area of the figure is 26.35 square inches.