Question

One end of a plastic pipe is capped and the other end is open. The pipe stands on the capped end in a magnetic field of 0.045 T that is aligned vertically. The pipe has an inside diameter of 7.0 cm. What is the magnetic flux through the plastic of the pipe?

Answer 1

Given:

Magnetic field, B = 0.045 T

Inside diameter = 7.0 cm

Let's find the magnetic flux through the plastic of the pipe.

To find the magnetic flux, apply the formula:

`\begin{gathered} \Phi=BA \\ \\ \Phi=BAcos\theta \end{gathered}`

Where:

• θ is the angle between the axis of the coil and the magnetic field.

In this case, θ = 180 degrees

• B = 0.045 T

• A is area = πr²

r is the radius in meters = diameter/ 2 = 0.07/2 = 0.035 m

Thus, plug in values in the formula and solve:

`\begin{gathered} \Phi=0.045*\pi *0.035^2cos180 \\ \\ \Phi=0.045\pi *-0.001225 \end{gathered}`

Solving further:

`\Phi=-1.7*10^(-4)\text{ Wb}`

Therefore, the magnetic flux through the plastic of the pipe is -1.7 x 10⁻⁴ Wb.

ANSWER:

-1.7 x 10⁻⁴ Wb