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Multiple (7/6a^7b^2)(5a^4b^6)

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We simply multiply the two terms and remember the multiplication rule of exponents where we add the exponents when multiplying same base. Shown below:


a^x* a^y=a^(x+y)

So, we multiply:


\mleft((7)/(6)a^7b^2\mright)\mleft(5a^4b^6\mright)​

Using the rule and multiplication, we have:


\begin{gathered} ((7)/(6)a^7b^2)(5a^4b^6)​ \\ =((7)/(6))(5)a^7a^4b^2b^6 \\ =\frac{35}{6^{}}a^(11)b^8 \end{gathered}

This is the final answer.

User Jeremywat
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