Question

What mass of oxygen can be obtained from heating 163.27 g of potassium chlorate?2KCIO₃ →2 KCl +30₂a. 28.42b. 1434c. 42.63d. 63.95

Answer 1

d. 63.95 g

Step-by-step explanation

Given:

Mass of potassium chlorate = 163.27 g

Equation: 2KCIO₃ → 2KCl +3O₂

What to find:

The mass of oxygen that can be produced from heating 163.27 g of KCIO₃.

Step-by-step solution:

From the given equation, 2 mol KClO₃ produced 3 mol O₂

Molar mass of KCIO₃ = 122.55 g/mol

2 mol KClO₃ = 2 mol x 122.55 g/mol = 245.10 g

Molar mass of O₂ = 31.998 g/mol

3 mol O₂ = 3 mol x 31.998 g/mol = 95.994 g

Therefore the mass of oxygen produced is calculated as follows:

`\begin{gathered} 245.10\text{ }g\text{ }KClO_3=95.994\text{ }g\text{ }O_2 \\ \\ 163.27\text{ }g\text{ }KClO_3=x \\ \\ x=\frac{163.27\text{ }g\text{ }KClO_3}{245.10\text{ }g\text{ }KClO_3}*95.994\text{ }g\text{ }O_2 \\ \\ x=63.95\text{ }g\text{ }O_2 \end{gathered}`

Thus, the mass of oxygen obtained from heating 163.27 g of KCIO₃ is 63.95 g.

The correct answer is option d. 63.95