In this problem, we are comparing the length of the Crazy Ant to the length of the Green anole.
Since we want to know how many times greater than anole is compared to the ant, we can use division to help us:

To find this, we can simply divide the Green Anoze's length by the Crazy Ant's length

Rewriting this, we have

Using fraction division, we get

Now we can cross cancel 6 and 3:

Simplify:

So, the correct answer is I. 64.