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graph y = x² + 2x - 8 and identify the zeros. Then determine which answer choice matches the graph that you drew and correctly identifies the zeros

graph y = x² + 2x - 8 and identify the zeros. Then determine which answer choice matches-example-1
graph y = x² + 2x - 8 and identify the zeros. Then determine which answer choice matches-example-1
graph y = x² + 2x - 8 and identify the zeros. Then determine which answer choice matches-example-2
User Sazz
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1 Answer

2 votes

STEP - BY - STEP EXPLANATION

What to find?

The zeros of the given equatiion.

The graph of the given equation.

Given:


y=x^2+2x-8

Step 1

Put y=0


x^2+2x-8=0

Step 2

Solving by factorization method;

Replace the coefficient of x, with two numbers whose product gives -8 and whose sum gives 2.

The numbers are: 4 and -2.


x^2+4x-2x-8=0

Step 3

Factorize;


\begin{gathered} x(x+4)-2(x+4)=0 \\ \\ (x+4)(x-2)=0 \end{gathered}

Step 4

Determine the x- values.

x = -4 and 2

Step 5

Write the quadratic equation in vertex form.


y=(x+1)^2-9

The vertex is (-1, -9). This implies the graph opens upward with a vertex (-1, -9).

ANSWER

graph y = x² + 2x - 8 and identify the zeros. Then determine which answer choice matches-example-1
User AdRock
by
7.5k points

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