STEP - BY - STEP EXPLANATION
What to find?
The zeros of the given equatiion.
The graph of the given equation.
Given:
![y=x^2+2x-8](https://img.qammunity.org/2023/formulas/mathematics/college/g2bksg9jyd9za3s92wfilx5bo8rm432t6p.png)
Step 1
Put y=0
![x^2+2x-8=0](https://img.qammunity.org/2023/formulas/mathematics/college/5icoy6vrpz6syd3oggk1mu4z04d0jqukix.png)
Step 2
Solving by factorization method;
Replace the coefficient of x, with two numbers whose product gives -8 and whose sum gives 2.
The numbers are: 4 and -2.
![x^2+4x-2x-8=0](https://img.qammunity.org/2023/formulas/mathematics/college/1w3v1jmca0yugk9lplq0cd3qa0aipgnqog.png)
Step 3
Factorize;
![\begin{gathered} x(x+4)-2(x+4)=0 \\ \\ (x+4)(x-2)=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/y4l7hxmpbwmqss6394ikpewujmbhlbr4r8.png)
Step 4
Determine the x- values.
x = -4 and 2
Step 5
Write the quadratic equation in vertex form.
![y=(x+1)^2-9](https://img.qammunity.org/2023/formulas/mathematics/college/h6tbt57wpbnbrdd9ohq6aztxiamr8q5584.png)
The vertex is (-1, -9). This implies the graph opens upward with a vertex (-1, -9).
ANSWER