From the given information, the probability that 4 new cereals will be produced and 2 are oats and 2 are rice is
![P(2\text{oats }\cap\text{ 2 rice)}=P(2\text{oats)}* P(2rice)](https://img.qammunity.org/2023/formulas/mathematics/college/ofci7nh5dtmv33it5hexbc1w43eynagw1e.png)
The first probability is given by
![P(2\text{oats)}=(5C2)/(12C4)](https://img.qammunity.org/2023/formulas/mathematics/college/8khhhn9pf8eo2m7qkpwri8x8qvodl4f1a0.png)
where 5C2 denotes the combination of 5 oats taken in 2. The second probability is given by
![P(2\text{rice)}=(4C2)/(12C4)](https://img.qammunity.org/2023/formulas/mathematics/college/s2ztms3rqxvaa9ln7y09tv38ht74nd6tf9.png)
Then the searched probability is
![\begin{gathered} P(2\text{oats }\cap\text{ 2 rice)}=P(2\text{oats)}* P(2rice) \\ P(2\text{oats }\cap\text{ 2 rice)}=(5C2)/(12C4)*(4C2)/(12C4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fiqhiy2yl9imb648ex1pe8iw75k1bch733.png)
which gives
![\begin{gathered} P(2\text{oats }\cap\text{ 2 rice)}=(10)/(495)*(6)/(495) \\ P(2\text{oats }\cap\text{ 2 rice)}=0.00024 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e59glk3wythffvond96gegrd2vbmy1sfxx.png)
then the answer is 0.00024.