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I need some help pls been out of school 7 weeks for covid and so confused

I need some help pls been out of school 7 weeks for covid and so confused-example-1
User Alf Eaton
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1 Answer

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Given:


3x+y=4\ldots\ldots\ldots\ldots\text{ take it as equation (1).}
6x+2y=8\ldots\ldots\ldots\ldots\text{ take it as equation (2).}

Multiply both sides of the equation (1) by 2, we get


(2)3x+(2)y=(2)4


6x+2y=8\ldots\ldots\ldots\ldots\text{ take it as equation (3).}

Subtract equation (2) from equation (3), we get


(6x+2y)-(6x+2y)=8-8
0=0

We obtain equation (2) by multiplying 2 and equation (1).

Equation 2 is dependent on equation (1).

We know that a dependent system has an infinite number of solutions.

The solution of the system has many solutions.

User Bruno Pereira
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