Answers:
(x)+(x+2)+(x+4) = 105 is the equation
The three consecutive odd integers are 33, 35, 37
33+35+37 = 105
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Work Shown:
x = first odd integer
x+2 = next consecutive odd integer
x+4 = third consecutive odd integer
The three items sum to 105
(x)+(x+2)+(x+4) = 105 is the equation
3x+6 = 105
3x = 105-6
3x = 99
x = 99/3
x = 33 is the first odd integer
x+2 = 33+2 = 35 is the second consecutive odd integer
x+4 = 33+4 = 37 is the third consecutive odd integer
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Check:
33+35+37 = 105
The answers are confirmed.