Part 3
we have
4x-3 < 13
solve for x
adds 3 both sides
4x-3+3 < 13+3
4x< 16
divide by 4 both sides
4x/4 < 16/4
x< 4
the solution is the interval (-infinite, 4)
All real numbers less than 4
In a number line the solution is the shaded area at left of x=4 (open circle)
see the attached figure
Part 4
we have
5x+10> 14x-8
solve for x
5x-14x > -8-10
-9x > -18
multiply by -1 both sides
9x < 18
divide by 9 both sides
x < 2
the solution is the interval (-infinite, 2)
In a number line the solution is the shaded area at left of x=2 (open circle)
see the attacjed figure
solve for x
adds 3