Given the expression:
![\sqrt[]{24(x-1)}/\sqrt[]{8x^2}](https://img.qammunity.org/2023/formulas/mathematics/college/nwhttfjnnrnm08cphf7swh1bi8mhk2mt7d.png)
Let's determine the inequality which represents all values of x where the quotient is defined.
Here, we are to find the domain.
Set the values in the radicand greater or equal to zero and solve for x.
We have:
![\begin{gathered} 24(x-1)\ge0 \\ \\ \text{Apply distributive property:} \\ 24x-24\ge0 \\ \\ 24x\ge24 \\ \\ \text{Divide both sides by 24:} \\ (24x)/(24)\ge(24)/(24) \\ \\ x\ge1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/drrp8gsjzrmr1g5np397pi0y2ruttd6pe9.png)
Set the denominator equal to zero and solve.
![\begin{gathered} 8x^2=0 \\ \\ x^2=(0)/(8) \\ \\ x=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/873ysoqwy4vornbq3bv1mcjcbtgkmlsj2u.png)
Here, the value of x should not be zero so the denominator will not tend to zero.
Therefore, we have:
x ≥ 1
This means the values of x where the expression is defined must be greater than or equal to 1.
ANSWER:
A. x ≥ 1