Question

Sara has 30 basketballsand 48 soccer balls. Whatis the greatest number ofgroups she can have thatwill use all of them so thateach group has the samenumber of basketballs andSoccer balls?

Answer 1

6 groups

Step-by-step explanation

We have to find the greatest common factor (GCF) between 30 and 48, because we want that each group have the same number of each ball.

First we have to write the factors of each of these numbers:

`\begin{gathered} 30\colon2,3,5,6,10,15 \\ 48\colon2,3,4,6,8,12,16,24 \end{gathered}`

From these two lists the greatest number that appears in both is 6. This is the GCF.

If we make 6 groups of balls, each group will have:

`\begin{gathered} 30/6=5 \\ 48/6=8 \end{gathered}`

5 basketballs and 8 soccer balls.