Question

A uniform electric field is established in the space within a parallel plate capacitor. Determine its magnitude if the plate separation is 3.60 cm and the capacitor is charged at a voltage of 62.00 V.

Answer 1

The electric field on a capacitor is given by:

`E=(V)/(d)`

where d is the distance between the plates and V is the voltage in the capacitor. In this case, the voltage is 62 V and the distance is 0.036 m; plugging these values we have:

`E=(62)/(0.036)=1722.22`

Therefore, the electric field i 1722.322 V/m