Question

An airplane flying at 222 meters per second passes over a region where Earth's magnetic field is 5.79 x 10-5 teslas and is nearly vertical. What voltage is induced between the plane's wing tips, which are 68.1 meters apart? Include units in your answer. Answer must be in 3 significant digits.

Answer 1

Given:

Velocity of the plane = 222 m/s

Magnetic field of the region = 5.79 x 10⁻⁵ T

Distance between wing tis = 68.1 m

Let's find the induced voltage between the plane's wing tips.

First apply the rate of change of area between the wing tips:

`r=v*d`

Where:

r is the rate of change of area

v is the velocity of plane

d is the distance between wing tips

Thus, we have:

`r=222*68.1=15118.2\text{ m}^2\text{ /s}`

Now, to find the induced voltage, apply the formula:

`v_(ind)=r*T`

Plug in the values and solve for the induced voltage:

`\begin{gathered} v_(ind)=15118.2*5.79*10^(-5) \\ \\ v_(ind)=0.875\text{ v} \end{gathered}`

Therefore, the induced voltage is 0.875 volts.

ANSWER:

0.875 v